Problem D1(alt) - Steady State Material Balanceson a Separation Train    |POLVER05_0
f(D1) = 0.07*D1+0.18*B1+0.15*D2+0.24*B2-0.15*70  #
f(B1) = 0.04*D1+0.24*B1+0.10*D2+0.65*B2-0.25*70  #
f(D2) = 0.54*D1+0.42*B2+0.54*D2+0.10*B2-0.40*70  #
f(B2) = 0.35*D1+0.16*B1+0.21*D2+0.01*B2-0.20*70  #
DD = D1+B1 #
BB = D2+B2 #
XDx = (0.07*D1+0.18*B1)/DD #
XDs = (0.04*D1+0.24*B1)/DD #
XDt = (0.54*D1+0.42*B1)/DD #
XDb = (0.35*D1+0.16*B1)/DD #
XBx = (0.15*D2+0.24*B2)/BB #
XBs = (0.10*D2+0.65*B2)/BB #
XBt = (0.54*D2+0.10*B2)/BB #
XBb = (0.21*D2+0.01*B2)/BB #
D1(0)=20
B1(0)=20
D2(0)=20
B2(0)=20